Answer:
The probability is 27%.
Step-by-step explanation:
We are not given the percentage value for the employees, so we choose an assumed percentage value of 35%
Also; Let assume that if 73% of the organization's employees both have more than ten years of experience and are college graduates ....
Using the Set theory:
Let represent the college graduates to be group A; &
Let represent the experienced employees to be group B.
A = 65% of the population
B = 35% of the population; &
A U B (union of A and B) = 73%.
The objective here is to determine the probability that a randomly selected employee will be either a college graduate or have more than ten years of experience (or both)
i.e We need to determine the size of A ∩ B ; which is read as : (intersection of A and B )
(i.e the group of college grads with 10 yrs experience).
Thus;
P( A U B) = P(A) + P(B) - P(A ∩ B )
P(A ∩ B) = P(A) + P(B) - P(A U B)
P(A ∩ B) = 0.65 + 0.35 - 0.73 = 0.27
Thus ,the probability is 27%.