Given: ABC, DE || AC
Prove: DA/BD = EC/BE

Drag and drop a reason to each box to complete the proof.

Drag options “can only be used once!”

Alternate Interior Angles Theorem

Corresponding Angles Postulate

Same-side interior angles theorem

Segment Addition Postulate

Transitive Property of Equality

Segment congruence postulate

Commutative property of addition

Addition property of equality

Substitutional property equality

Given ABC DE AC Prove DABD ECBE Drag and drop a reason to each box to complete the proof Drag options can only be used once Alternate Interior Angles Theorem Co class=

Respuesta :

Answer:

1. ∠BDE ≅ ∠ BAC                            Corresponding Angles Postulate

  ∠BED ≅ ∠BCA

2. BA = BD + DA

   BC = BE + EC                                Segment Addition Postulate

3.   BD + DA / BD = BE + EC / BE     Substitutional property equality

Step-by-step explanation:

Answer:

1. ∠BDE ≅ ∠ BAC                            Corresponding Angles Postulate

 ∠BED ≅ ∠BCA

2. BA = BD + DA

  BC = BE + EC                                Segment Addition Postulate

3.   BD + DA / BD = BE + EC / BE     Substitutional property equality

Step-by-step explanation:

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