Factor completely 5x4 − 80.


5(x2 − 4)(x2 + 4)

5(x − 2)(x + 2)(x + 2)(x + 2)

5(x − 2)(x + 2)(x2 − 4)

5(x − 2)(x + 2)(x2 + 4)

Respuesta :

Answer:

[tex]5(x - 2)(x+ 2)(x^2 + 4)[/tex]

Step-by-step explanation:

The expression given is:

[tex]5x^4 - 80\\\\5(x^4 - 16)\\\\5(x^4 - 2^4)\\\\5((x^2)^2 - (2^2)^2)\\\\[/tex]

Difference of two squares:

[tex]5(x^2 - 2^2)(x^2 + 2^2)\\\\5(x - 2)(x + 2)(x^2 + 2^2)\\\\5(x - 2)(x+ 2)(x^2 + 4)[/tex]

The factorized form of the given equation is [tex]5(x-2)(x+2)(x-2)(x+2)[/tex] and this can be determined by using the factorization method.

Given :

[tex]f(x) = 5x^4-80[/tex]

The following steps can be used in order to determine the factors of the given function:

Step 1 - Write the given function.

[tex]f(x) = 5x^4-80[/tex]

Step 2 - Take out 5 as common in the above function.

[tex]f(x) = 5(x^4-16)[/tex]

Step 3 - Now, try to factorize the above function.

[tex]f(x) = 5(x^4-2^4)\\f(x) = 5(x-2)(x+2)(x-2)(x-2)[/tex]

From the above steps, it can be concluded that the correct option is B).

For more information, refer to the link given below:

https://brainly.com/question/6810544