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A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 3.60 m/s. The car is a distance d away. The bear is 39.3 m behind the tourist and running at 5.00 m/s. The tourist reaches the car safely. What is the maximum possible value for d

Respuesta :

MathPhys

Answer:

101 meters

Explanation:

Distance traveled by the tourist:

d = 3.60 m/s × t

Distance traveled by the bear:

d + 39.3 m = 5.00 m/s × t

Substitute:

3.6 t + 39.3 = 5 t

39.3 = 1.4 t

t = 28.1

d = 101

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