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An observer (O) spots a plane (P) taking off from a local airport and flying at a 33° angle horizontal to her line of sight and located directly above a tower (T). The observer also notices a bird (B) circling directly above her. If the distance from the plane(P) to the tower (T) is 7,000 ft., how far is the bird (B) from the plane (P)? Round to the nearest whole number. (4 points)
Angle P a 3815 feet b 5873 feet c 8343 feet d 10,779 feet
please see attatchment

An observer O spots a plane P taking off from a local airport and flying at a 33 angle horizontal to her line of sight and located directly above a tower T The class=

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Answer:

Option D. 10,779 feet

Step-by-step explanation:

Given from the figure attached,

PT = OB = 7000 ft

PB = OT = x feet

and angle of elevation (∠POT) = 30°

By applying Tan rule in the triangle POT,

tan33° = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}[/tex] = [tex]\frac{PT}{OT}[/tex]

tan33° = [tex]\frac{7000}{x}[/tex]

x = [tex]\frac{7000}{\text{tan}33}[/tex]

x = 10779 feet

Therefore, distance between the bird (B) and plane (P) is 10,779 feet.

Option D. will be the answer.

crystalice

Answer:

10,779 feet

Step-by-step explanation:

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