Answer:
[tex] S =4\pi r^2[/tex]
And since we know the surface area 326.7 in^2 we can solve for the value of r like this:
[tex] r =\sqrt{\frac{S}{4 \pi}}[/tex]
And replacing we got:
[tex] r =\sqrt{\frac{326.7 in^2}{4 (3.14)}}= 5.10 in[/tex]
And the best answer would be:
5.1 in
Step-by-step explanation:
For this case we need to use the formula for the surface area of a sphere given by:
[tex] S =4\pi r^2[/tex]
And since we know the surface area 326.7 in^2 we can solve for the value of r like this:
[tex] r =\sqrt{\frac{S}{4 \pi}}[/tex]
And replacing we got:
[tex] r =\sqrt{\frac{326.7 in^2}{4 (3.14)}}= 5.10 in[/tex]
And the best answer would be:
5.1 in
Answer:
5.1
Step-by-step explanation:
The equation for the surface area of a sphere is SA=4πr2 (that is squared, not a 2)
So plug in the known values:
326.7=4(3.14)r2 Multiply 4 x 3.14
326.7=12.56r2 Divide by 12.56
26.0111=r2 Get the square root
5.0110=r
This simplifies to 5.1, which is the maximum radius of the globe.
I would recommend going back to the course and writing all of the equations on page 6 down, or printing the segment review page from resources in the course. This will hwlp you with those problems in the future.
