Answer:
e% = 2.2%
Explanation:
In the measurements it is very important the precision of the readings and the knowledge of how the uncertainty or errors in each measurement propagates when carrying out the different calculations
In this case the area of the body is its length l = 5.9 mm, for its width a = 4.1 mm
S = l a
The error can be calculated using derivatives and considered the worst of all cases
Δs = ds /dl Δl + dS /da Δa
in this case the derivatives are very simple
dS / dl = a
dS / Da = l
we substitute
ΔS = a Δl + l Δa
this is the absolute error
Let's calculate its value
Δs = 4.1 0.05 + 5.1 0.05
Δs = 0.5 mm²
the percentage error is this error between the magnitude of the mediated by 100
e% = ΔS / S 100
e% = 0.5 / (5.1 4.1) 100
e% = 2.2%
