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What is the equation of the line that is perpendicular to the linear
graph of y= -2/3x+5 and passes through the point (0, -2)?

What is the equation of the line that is perpendicular to the linear graph of y 23x5 and passes through the point 0 2 class=

Respuesta :

sharonkaran

Answer:

y=3/2x-2

Step-by-step explanation:

gradient line 1= -2/3

perpendicular meaning gradients when multiplied should be -1

gradient line 2=3/2

y+2=3/2

x-0

y+2=3/2(x-0)

y+2=3/2x-0

y=3/2x-2

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