Answer:
One-eighth of an hour
Explanation:
Given that Carrington used 3/4 of the 1/2 of an hour allotted for an exam to do the first 3 problems.
We are to calculate the time that he has left for the remaining part of the exam.
We have
Total time used i the first three problems is given by
[tex]\frac{3}{4}[/tex]×[tex]\frac{1}{2}[/tex]= [tex]\frac{3}{8}[/tex]
Therefore, the time left to complete the remaining part of the exam will be
Tr= [tex]\frac{1}{2}[/tex] - [tex]\frac{3}{8}[/tex]= [tex]\frac{4-3}{8}[/tex]=[tex]\frac{1}{8}[/tex] hour
