Respuesta :

Answer:

A(√2) would be the correct answer.

Answer:

[tex] \boxed{A. \: \sqrt{2} \: \: \: and \: \: \: F. \: \frac{ \sqrt{4} }{ \sqrt{2} }} [/tex]

Step-by-step explanation:

[tex] = > \frac{ \sqrt{18} }{ \sqrt{9} } = \frac{ \sqrt{9 \times 2} }{ \sqrt{9} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{ \cancel{ \sqrt{9}} \times \sqrt{2} }{ \cancel{ \sqrt{9} }} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{2} [/tex]

[tex]F. \: \frac{ \sqrt{4} }{ \sqrt{2} } = \frac{ \sqrt{2 \times 2} }{ \sqrt{2} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{ \cancel{\sqrt{2}} \times \sqrt{2} }{ \cancel{\sqrt{2}}} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{2} [/tex]