Answer:
[tex]2c^{2}[/tex]
Step-by-step explanation:
[tex]\frac{8c^33d^2}{4cd^2}[/tex]
[tex]\frac{2c^2d^0}{1}[/tex]
[tex]2 {c}^{2} [/tex]
[tex] \frac{8 {c}^{3} {d}^{2} }{4 {c}^{1} {d}^{2} } \\ = 2 {c}^{3 - 1} {d}^{2 - 2} \\ = 2 {c}^{2} {d}^{0} [/tex]
we know that,
[tex] {d}^{0} = 1[/tex]
so,
[tex] = 2 {c}^{2} {d}^{0} \\ = 2 \times {c}^{2} \times 1 \\ = 2 {c}^{2} [/tex]
hope this helps
brainliest appreciated
good luck! have a nice day!
