Answer:
0.08 J
Explanation:
EE = ½ kx²
EE = ½ (400 N/m) (0.02 m)²
EE = 0.08 J
The energy stored in the spring, if the force constant is 400N/m is 0.08 J.
When the spring is compressed, it gets compressed up to its elastic limit. When load is removed from the spring, it regains its shape and obtains equilibrium position. The energy stored in this process is called as spring potential energy.
Given a spring is compressed by 0.02m. The force constant is 400N/m. The energy stored in the spring is given by
SPE = ½ kx²
SPE = ½ (400 N/m) (0.02 m)²
SPE = 0.08 J
Thus, the energy stored in the spring is 0.08 J.
Learn more about spring potential energy.
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