Answer:
[tex]\frac{x^2}{16} +xy+4y^2[/tex] can be factored out as: [tex](\frac{x}{4} +2\,y)^2[/tex]
Step-by-step explanation:
Recall the formula for the perfect square of a binomial :
[tex](a+b)^2=a^2+2ab+b^2[/tex]
Now, let's try to identify the values of [tex]a[/tex] and [tex]b[/tex] in the given trinomial.
Notice that the first term and the last term are perfect squares:
[tex]\frac{x^2}{16} = (\frac{x}{4} )^2\\4y^2=(2y)^2[/tex]
so, we can investigate what the middle term would be considering our [tex]a=\frac{x}{4}[/tex], and [tex]b=2y[/tex]:
[tex]2\,a\,b=2\,(\frac{x}{4}) \,(2\,y)=x\,y[/tex]
Therefore, the calculated middle term agrees with the given middle term, so we can conclude that this trinomial is the perfect square of the binomial:
[tex](\frac{x}{4} +2\,y)^2[/tex]
