Calculate Keq for these reactions and predict if the equilibrium will lie to the right or to the left as written. (You may enter your answer in scientific notation, e.g. 1.0*10^-9. Enter your answer to two significant figures.) Reaction 1: + + pKa = 9 pKa = 38 Keq = Equilibrium position = _ Reaction 2: + + pKa = 35 pKa = 25 Keq = Equilibrium position = _

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okpalawalter8 okpalawalter8 · Answer 1 · 2020-06-11T05:05:38+02:00

Complete Question

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Answer:

For reaction 1

[tex]K_{eq} = 10^{29}[/tex]

The equilibrium position is to the right

For reaction 2

The equilibrium position is to the left

Explanation:

Generally [tex]pKa[/tex] is mathematically evaluated as

[tex]pKa = pKa _ \ {left }} - pKa _ \ {right }}[/tex]

And equilibrium position [tex]K_a[/tex] is mathematically evaluated as [tex]K_{eq} = 10^\ {-pK_a}[/tex]

From the question we are told that

For reaction 1

[tex]pKa_\ {left}} \ = 9[/tex]

[tex]pKa_\ {right }} \ = 38[/tex]

So

[tex]pKa = 9-38[/tex]

[tex]pKa =-29[/tex]

So [tex]K_{eq} = 10^{-(-29)}[/tex]

[tex]K_a = 10^{29}[/tex]

This implies that the equilibrium position is to the right

For reaction 2

[tex]pKa_\ {left}} \ = 15.9[/tex]

[tex]pKa_\ {right }} \ = 9.24[/tex]

So

[tex]pKa = 15.9-9.24[/tex]

[tex]pKa = 6.66[/tex]

So [tex]K_{eq} = 10^{-(6.66)}[/tex]

[tex]K_{eq} = 10^{-6.66}[/tex]

This implies that the equilibrium position is to the left