Answer:
The horizontal distance the ball travels before returning to the ground is 19.5 m
Step-by-step explanation:
Formula of range of horizontal distance =[tex]\frac{u^2 Sin 2 \theta}{g}[/tex]
Where u is the initial velocity
g is gravity
We are given that A ball is kicked off the ground with a velocity of 15 m/s at an angle of 30° horizontally.
So, u = 15 m/s
[tex]\theta = 30^{\circ}[/tex]
g = 10
So, the horizontal distance the ball travels before returning to the ground = [tex]\frac{15^2 Sin 2(30^{\circ})}{10}=19.48 \sim 19.5 m[/tex]
Hence The horizontal distance the ball travels before returning to the ground is 19.5 m
