Answer:
Denote that line: y = ax + b
Line passes (-2, 7) and (2,-5):
=> -2a + b =7
=> 2a + b = -5
Add both side of above equations:
=> 2b = 2
=> b = 1
=> a = (-5 - 1)/2 = -3
=> Slope a = -3
Hope this helps!
:)
This question is based on the equation of line. Therefore, the slope of the line is -3 that passes through the points (-2, 7) and (2,-5).
Given:
Points are (-2, 7) and (2,-5).
We need to calculate the slope of the line that passes through the points (-2, 7) and (2,-5).
According to the question,
As we know that, equation of line: y = mx +c
It is given that, line passes through points, (-2, 7) and (2,-5).
Now, putting this points in equation of line: y = mx +c.
We get,
=> -2m + c =7 ...(1)
=> 2m + c = -5 ...(2)
Now, adding and solving above two equations,
We get, c = 1
Then, putting the value of b= 1 in equation (1).
We get, m = -3.
Therefore, the slope of the line is -3 that passes through the points (-2, 7) and (2,-5).
For more details, prefer this link:
https://brainly.com/question/21511618
