Answer:
Moles: [tex]n=0.127mol[/tex]
Molar mass: [tex]M=200.61 g/mol[/tex]
Explanation:
Hello,
In this case, we can use the ideal gas equation to compute the moles of the gas sample as shown below:
[tex]PV=nRT\\\\n=\frac{PV}{RT}[/tex]
Thus, we should use the pressure in atm as follows:
[tex]n=\frac{80.0kPa*\frac{0.00986923atm}{1kPa}*4.00L}{0.082\frac{atm*L}{mol*K}*303K}\\ \\n=0.127mol[/tex]
Moreover, the molar mass is obtained by dividing the given mass by the obtained moles:
[tex]M=\frac{m}{n}=\frac{25.50g}{0.127mol}\\ \\M=200.61 g/mol[/tex]
Best regards.
