In ΔHIJ, the measure of ∠J=90°, the measure of ∠H=84°, and HI = 69 feet. Find the length of IJ to the nearest tenth of a foot.
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Answer:
The length of IJ is 68.7 feet.
Step-by-step explanation:
According to trigonometric identities for a right angled triangle, the sin of an angle is:
[tex]sin\ \theta=\frac{\text{Perpendicular}}{\text{Hypotenuse}}[/tex]
From the provided data we can interpret that:
Perpendicular = x feet
Hypotenuse = 69 feet
θ = 84°
Compute the value of x as follows:
[tex]sin\ \theta=\frac{\text{Perpendicular}}{\text{Hypotenuse}}[/tex]
[tex]sin\ 84^{\text{o}}=\frac{x}{69}\\\\0.995=\frac{x}{69}\\\\x=69\times0.995\\\\x=68.655\\\\x\approx 68.7[/tex]
Thus, the length of IJ is 68.7 feet.