Answer:
[tex]y=\pm\text{ }i\sqrt{\frac{1}{2}}[/tex]
Step-by-step explanation:
So we first multiply out the parentheses, which turns out to be [tex]-18y^2[/tex]. So our equation is [tex]-18y^2 + 9 = 0[/tex]. We factor out a 9, which turns into [tex]9(2y^2+1)[/tex]. So [tex]2y^2+1=0.[/tex] Solving, we have [tex]y^2=-\frac{1}{2}[/tex], and [tex]y=\pm\text{ }i\sqrt{\frac{1}{2}}[/tex]. I'm sorry everything is so messy, I hope you can still understand.
