Any help someone....
(solve triangles using the law of sines)

Answer:
[tex]B=51[/tex]°
Step-by-step explanation:
Use the Law of Sines as follows:
[tex]\frac{sinC}{c} =\frac{sinB}{b}[/tex]
Insert the appropriate values:
[tex]\frac{sin100}{14} =\frac{sinB}{11}[/tex]
Isolate B. Multiply both sides by 11:
[tex]11*(\frac{sin100}{14} )=11*(\frac{sinB}{11})\\\\\frac{11*sin100}{14} =sinB\\\\sinB=\frac{11*sin100}{14}[/tex]
Use the inverse:
[tex]B=sin^{-1}(\frac{11*sin100}{14})[/tex]
Insert the equation into a calculator and round to the nearest degree:
[tex]B=50.7\\\\B=51[/tex]
Angle B is 51°.
:Done