Respuesta :
Answer:
Probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.
Step-by-step explanation:
We are given that the amount a Niffler can hold in their pouch is approximately normally distributed with a mean of 25 pounds of shiny objects and a standard deviation of 6.8 pounds.
Let X = amount a Niffler can hold in their pouch
So, X ~ Normal([tex]\mu=25,\sigma^{2} =6.8^{2}[/tex])
The z score probability distribution for normal distribution is given by;
Z = [tex]\frac{X-\mu}{\sigma}[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = population mean = 25 pounds
[tex]\sigma[/tex] = standard deviation = 6.8 pounds
Now, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is given by = P(X > 32 pounds)
P(X > 32 pounds) = P( [tex]\frac{X-\mu}{\sigma}[/tex] > [tex]\frac{32-25}{6.8}[/tex] ) = P(Z > 1.03) = 1 - P(Z [tex]\leq[/tex] 1.03)
= 1 - 0.8485 = 0.1515
The above probability is calculated by looking at the value of x = 1.03 in the z table which has an area of 0.8485.
Hence, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.