Answer:
The distance from the helicopter to the fire is 8909 feet.
Step-by-step explanation:
Refer the attached figure
The pilot of a helicopter sights a fire at an angle of depression of 11° i.e. [tex]\angle ACB = 11^{\circ}[/tex]
The helicopter's altitude is 1700 feet.i.e.AB = 1700 feet
We are supposed to find the distance from the helicopter to the fire i.e. AC
Using trigonometric ratios
[tex]Sin \theta = Perpendicular}{Hypotenuse}\\\\Sin 11^{\circ}=\frac{AB}{AC}\\\\Sin 11^{\circ}=\frac{1700}{AC}\\\\AC=\frac{1700}{Sin 11^{\circ}}\\\\AC=\frac{1700}{0.1908}\\\\AC=8909.85 feet[/tex]
Hence the distance from the helicopter to the fire is 8909 feet.
