Answer:
A) FeCl₃
Explanation:
The only unclear part here is what the product is meant to be. But, I will put in the limiting reactant for both cases.
4 FeCl₃ + 3 O₂ ⇒ 2 Fe₂O₃ + 3 Cl₂
For Fe₂O₃:
Use the stoichiometry from the chemical equation to solve this problem.
You need 4 moles of FeCl₃ to make 2 moles of Fe₂O₃.
8 × (2/4) = 4 moles
You need 3 moles of O₂ to make 2 moles of Fe₂O₃.
8 × (2/3) = 5.3 moles
Since FeCl₃ made less product, it is the limiting reactant.
For Cl₂:
Do the same as above.
You need 4 moles of FeCl₃ to make 3 moles of Cl₂.
8 × (3/4) = 6 moles
You need 3 moles of O₂ to make 3 moles of Cl₂.
8 × (3/3) = 8 moles
Since FeCl₃ made less product, it is the limiting reactant.
