Answer:
The change in momentum is [tex]\Delta p = 0.7 \ kg\cdot m \cdot s^{-1}[/tex]
Explanation:
From the question we are told that
The time taken for the stone to stop is [tex]\Delta t = 0.15 \ seconds[/tex]
The net force on the rock is [tex]F = 58 \ N[/tex]
The impulse of the rock can be mathematically represented as
[tex]I = F * \Delta t[/tex]
Substituting values
[tex]I = 58 * 0.15[/tex]
[tex]I = 0.7\ kg * m * s^{-1}[/tex]
Now impulse is defined as the rate at which momentum change
Hence the change in momentum [tex]\Delta p[/tex] of the rock is equal to the impulse of the rock
So
[tex]\Delta p = I = 0.7 \ kg\cdot m \cdot s^{-1}[/tex]
