Respuesta :
Answer:
[tex]z=\frac{46300-50000}{\frac{9800}{\sqrt{28}}}=-1.998[/tex]
Now we can calculate the p value using the alternative hypothesis with this probability:
[tex]p_v =P(z<-1.998)=0.0229[/tex]
The p value for this case is significantly lower than the value of [tex]\alpha=0.05[/tex] so then we can reject the null hypothesis at this signficance level and we have enough evidence to conclude that the true mean for the deluxe tire is less than 50000 and the claim is not correct.
Step-by-step explanation:
Information given
[tex]\bar X=46300[/tex] represent the sample mean for the lifespans
[tex]\sigma=9800[/tex] represent the population standard deviation
[tex]n=28[/tex] sample size
[tex]\mu_o =50000[/tex] represent the value to verify
[tex]\alpha=0.05[/tex] represent the significance level
z would represent the statistic
[tex]p_v[/tex] represent the p value
System of hypothesis
The idea for this case is verify if the deluxe tire averages at least 50,000, so then the system of hypothesis are:
Null hypothesis:[tex]\mu \geq 50000[/tex]
Alternative hypothesis:[tex]\mu < 50000[/tex]
We know the population deviation so then the correct test stattistic would be:
[tex]z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}[/tex] (1)
Replacing the info given we got:
[tex]z=\frac{46300-50000}{\frac{9800}{\sqrt{28}}}=-1.998[/tex]
Now we can calculate the p value using the alternative hypothesis with this probability:
[tex]p_v =P(z<-1.998)=0.0229[/tex]
The p value for this case is significantly lower than the value of [tex]\alpha=0.05[/tex] so then we can reject the null hypothesis at this signficance level and we have enough evidence to conclude that the true mean for the deluxe tire is less than 50000 and the claim is not correct.