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On a coordinate plane, a circle has a center at (4, 5) and a radius of 3 units.
Which equation represents a circle with the same center as the circle shown but with a radius of 2 units?

(x – 4)2 + (y – 5)2 = 2
(x – 4)2 + (y – 5)2 = 4
(x – 5)2 + (y – 4)2 = 2
(x – 5)2 + (y – 4)2 = 4

Respuesta :

Answer:

(x - 4)² + (y - 5)² = 4

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = (4, 5) and r = 2, thus

(x - 4)² + (y - 5)² = 2², that is

(x - 4)² + (y - 5)² = 4 ← second option on list

abidemiokin

The required equation represents a circle with the same center as the circle shown but with a radius of 2 units is (x-4)^2  + (y-5)^2 = 4

Equation of a circle

The standard equation of a circle is expressed as:

(x-a)^2  + (y-b)^2 = r^2

where:

(a, b) is the centre = (4, 5)

r is the radius = 3 units

Substitute to have;

(x-4)^2  + (y-5)^2 = 2^2

(x-4)^2  + (y-5)^2 = 4

Hence the required equation represents a circle with the same center as the circle shown but with a radius of 2 units is (x-4)^2  + (y-5)^2 = 4

Learn more on equation of circle here: https://brainly.com/question/14150470