Answer: The climb angle is 14°
Step-by-step explanation:
We can create a rectangle triangle, where the velocity of the plane is the hypotenuse, the horiontal component (1000 ft by unit of time) is a cathetus and the vertical component is (250ft by unit of time).
We want to find the angle that is adjacent to the horizontal component, so we can use the relationship.
Tan(angle) = opposite cathetus/adjacent cathetus
Tan(angle) = 250/1000 = 1/4
Angle = Atan(1/4) = 14°
The airplane's climbing angle is 14.04°
The plane is climbing 250 feet for every 1000 feet it travels.
This means for every 250 feet vertical movement the plane makes an horizontal movement of 1000 feet. Therefore, the airplanes climbing angle can be computed as follows:
Let
∅ = climbing angle
Therefore,
opposite side = 250 ft
adjacent side = 1000 ft
tan ∅ = 250 / 1000
∅ = tan ⁻¹ 0.25
∅ = 14.0362434679
∅ = 14.04°
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