Answer:
[tex]V_{2} = 29.28\,L[/tex]
Explanation:
Let assume that gas behaves ideally and experiments an isobaric and isothermal processes. The following relationship is applied to determined the final volume:
[tex]\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}[/tex]
[tex]V_{2} = V_{1} \cdot \left(\frac{n_{2}}{n_{1}} \right)[/tex]
[tex]V_{2} = (12.2\,L)\cdot \left(\frac{16.8\,moles}{7\,moles} \right)[/tex]
[tex]V_{2} = 29.28\,L[/tex]
