Respuesta :

MathPhys

Answer:

8. -⅓ cos³x + C

9. sec x + eˣ + C

Step-by-step explanation:

8. ∫ sin x cos²x dx

If u = cos x, then du = -sin x dx.

∫ -u² du

-⅓ u³ + C

-⅓ cos³x + C

9. ∫ (sec x tan x + eˣ) dx

∫ sec x tan x dx + ∫ eˣ dx

These are both standard integrals:

sec x + eˣ + C

Wolfyy

Question 8:

∫sinxcos²xdx

∫-u²du (let u = cos(x))

-∫u²du

-u(^2+1)/2+1

-cos^(2+1)(x)/2+1

-1/3cos³(x)

-1/3cos³(x) + C

Question 9:

∫(secxtanx + eˣ)dx

∫sec(x)tan(x)dx + ∫eˣdx (apply sum rule)

sec(x) + eˣ (sec(x)tan(x)dx = sec(x) and eˣdx = eˣ)

sec(x) + eˣ + C

Best of Luck!

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