Answer: 16700 Joules
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
[tex]Q=m\times c\times \Delta T[/tex]
Q = Heat absorbed = ?
m = mass of sand = 2 kg
c = heat capacity = [tex]835J/kg^0C[/tex]
Initial temperature = [tex]T_i[/tex] = [tex]40^0C[/tex]
Final temperature= [tex]T_f[/tex] = [tex]50^0C[/tex]
Change in temperature ,[tex]\Delta T=T_f-T_i=(50-40)^0C=10^0C[/tex]
Putting in the values, we get:
[tex]Q=2kg\times 835J/kg^0C\times 10^0C[/tex]
[tex]Q=16700J[/tex]
16700 J of energy must be added to a 2-kilogram pile of it to increase its temperature from 40°C to 50°C
