A wheel with radius 1 foot makes 1 revolution in 4 seconds. What is the linear velocity, in feet per second, of a point on the edge of the wheel?

Respuesta :

In one revolution of the wheel, a point on the edge travels a distance equal to the circumference of the wheel.

The wheel has radius 1 ft, so its circumference is 2π (1 ft) = 2π ft.

Then the point has a linear speed of

(1/4 rev/s) * (2π ft/rev) = 2π/4 ft/s = π/2 ft/s

Answer:

π/2 ft/s

Step-by-step explanation: