Respuesta :

wegnerkolmp2741o

Answer:

see below

Step-by-step explanation:

8.

We have to use the law of cosines to find AB

c^2 = a^2 + b^2 − 2ab cos(C)

AB^2 = 14^2 + 24^2 - 2 * 14 *24 cos(91)

AB^2 =196 +576 - 672 cos(91)

AB^2 =783.7280171

Taking the square root of each side

AB =27.99514

Rounding to the nearest tenth

AB = 28

(If the lengths are supposed to have the variable A)

AB = 28A

9.

Using the law of sines

sin 84              sin A

--------------  = -------------

22                     9

Using cross products

9 sin 84 = 22 sin A

Divide each side by 22

9 sin 84 /22 = sin A

.406849866 = sin A

Taking the inverse sin of each side

24.00710132 = A

To the nearest tenth

A = 24

mathstudent55

Answer:

AB = 28 ft; m<A = 24 deg

Step-by-step explanation:

8.

Since you are not given an angle and its opposite side, you cannot start with the law of sines. You must use the law of cosines.

[tex] c^2 = a^2 + b^2 - 2ab \cos C [/tex]

[tex] c^2 = (14~ft)^2 + (24~ft)^2 - 2(14~ft)(24~ft) \cos 91^\circ [/tex]

[tex] c^2 = 196~ft^2 + 576~ft^2 - 672~ft^2(-0.01745) [/tex]

[tex] c = \sqrt{783.73~ft^2} [/tex]

[tex] c = 27.995~ft [/tex]

AB = c = 28 ft

9.

[tex] \dfrac{\sin A}{a} = \dfrac{\sin B}{b} = \dfrac{\sin C}{c} [/tex]

[tex] \dfrac{\sin A}{a} = \dfrac{\sin B}{b} [/tex]

[tex] \dfrac{\sin A}{9~km} = \dfrac{\sin 84^\circ}{22~km} [/tex]

[tex] \sin A = \dfrac{9~km~\sin 84^\circ}{22~km} [/tex]

[tex] \sin A = 0.40685 [/tex]

[tex] A = \sin^{-1} 0.40685 [/tex]

[tex] A = 24^\circ [/tex]

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