Answer:
1)x=21.33
2)Height of tree is 20 m
Step-by-step explanation:
Question 1
ΔABC ≈ΔADE
Property of similar triangles :Corresponding sides of similar triangles are all in the same proportion
So,[tex]\frac{AB}{AD}=\frac{BC}{DE}\\\frac{AB}{AB+BD}=\frac{BC}{DE}\\\frac{12}{12+6}=\frac{x}{32}\\\frac{12}{18}=\frac{x}{32}\\\frac{12}{18} \times 32 =x\\21.33=x[/tex]
Question 2: Find the height of tree
ΔDEF ≈ΔDHI
Property of similar triangles :Corresponding sides of similar triangles are all in the same proportion
So,[tex]\frac{DE}{DH}=\frac{EF}{HI}\\\frac{3}{30}=\frac{2}{HI}\\HI=\frac{2 \times 30}{3}\\HI=20[/tex]
Hence The height of tree is 30 m
