Answer:
10moles of NH₃ will produce 660g of (NH₄)₂SO₄
Explanation:
Equation of reaction:
2NH₃ + H₂SO₄ → (NH₄)₂SO₄
2 mole of NH₃ = 1 Mole of (NH₄)₂SO₄
Molar mass of NH₃ = [14 + (3*1)] = 17g/mol
Number of moles = mass / molarmass
Mass = number of mole * molarmass
Mass = 2 * 17 = 34g
Molar mass of (NH₄)₂SO₄ = [(14 + 4)*2 + (32 + 64)
Molar mass of (NH₄)₂SO₄ = 132g/mol
Mass = molar mass * number of moles
Mass = 132 * 1 = 132g
From the equation of reaction,
34g of NH₃ will produce 132g of (NH₄)₂SO₄
34g of NH₃ = 132g of (NH₄)₂SO₄
X g of NH₃ = 660g of (NH₄)₂SO₄
X = (34*660) / 132
X = 170g of NH₃
170g of NH₃ will produce 660g of (NH₄)₂SO₄
Number of moles = mass / molarmass
Molar mass of NH₃ = 17g/mol
Number of moles = 170 / 17
Number of moles = 10moles
Therefore 10moles of NH₃ will produce 660g of (NH₄)₂SO₄
