Respuesta :
Answer:
7/18
Step-by-step explanation:
First we need to find what values of sum we can have.
The minimum value for a cube is 1, so the minimum value for the sum is 2.
The maximum value for a cube is 6, so the maximum value for the sum is 12.
Now, we find the multiples of 6 and the multiples of 4 between 2 and 12:
4, 6, 8, 12.
To have a sum of 4, we can have the pairs:
(1,3), (2,2), (3,1)
To have a sum of 6, we can have the pairs:
(1,5), (2,4), (3,3), (4,2), (5,1)
To have a sum of 8, we can have the pairs:
(2,6), (3,5), (4,4), (5,3), (6,2)
To have a sum of 12, we can have the pairs:
(6,6)
So we have 14 pairs among the 36 (6 possibilities of each cube, so 6*6=36) total possibilities of pairs, so the probability is P = 14/36 = 7/18
The probability that the outcome of the roll is a sum that is a multiple of 6 or a sum that is a multiple of 4 is, [tex]P(E)=\frac{14}{36}=\frac{7}{18}[/tex]
The probability of any event is computed as divide number of favourable outcomes by total number of outcomes.
The sum that is a multiple of 6 or a sum that is a multiple of 4 are 4, 6, 8 and 12.
For sum of 4, we can have the pairs = (1,3), (2,2), (3,1)
For sum of 6, we can have the pairs: = (1,5), (2,4), (3,3), (4,2), (5,1)
For sum of 8, we can have the pairs = (2,6), (3,5), (4,4), (5,3), (6,2)
For sum of 12, we can have the pairs = (6,6)
Total number of favourable outcomes = 14
When two distinct number cubes are rolled. then,
Total number of outcomes [tex]=6^{2}=36[/tex]
The probability that the outcome of the roll is a sum that is a multiple of 6 or a sum that is a multiple of 4,
[tex]P(E)=\frac{14}{36}=\frac{7}{18}[/tex]
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