Find , to the nearest tenth of a foot , the height of the tree represented in the accompanying diagram.

Answer:
Height of tree = 28.2 ft (Approx)
Step-by-step explanation:
Given:
Angle from ground to top of the tree = 62°
Distance from a point to base of tree = 15 ft
Height of tree = [tex]X[/tex]
Find:
Height of tree = [tex]X[/tex]
Computation:
Using trigonometric application:
[tex]Tan\ 62 = \frac{Height\ of\ tree}{Distance\ from\ a\ point\ to\ base\ of\ tree} \\\\Using\ calculator\ , Tan62 = 1.88\\\\1.88=\frac{Height\ of\ tree}{15} \\\\Height\ of\ tree=28.2ft[/tex]
Height of tree = 28.2 ft (Approx)