Answer:
1.61 mL
Explanation:
Step 1:
Data obtained from the question. This includes the following:
Initial volume (V1) = 1.35 mL
Initial pressure (P1) = 125 kPa
Final pressure (P2) = 105 kPa
Final volume (V2) =..?
Step 2:
Determination of the volume of the air bubble at the surface of the lake.
This can be obtained by use the Boyle's law equation as follow:
P1V1 = P2V2
125 x 1.35 = 105 x V2
Divide both side by 105
V2 = (125 x 1.35)/105
V2 = 1.61 mL
Therefore, the volume of the air bubble at the surface of the lake is 1.61 mL
