Answer:
The answer is √5 .
Step-by-step explanation:
You have to rationalize the fraction in order to get rid of surd in the denorminator by multiplying √3 to both numerator amd denorminator :
[tex] \frac{ \sqrt{15} }{ \sqrt{3} } [/tex]
[tex] = \frac{ \sqrt{15} }{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } [/tex]
[tex] = \frac{ \sqrt{15} \times \sqrt{3} }{ \sqrt{3} \times \sqrt{3} } [/tex]
[tex] = \frac{ \sqrt{45} }{3} [/tex]
[tex] = \frac{ \sqrt{9 \times 5} }{3} [/tex]
[tex] = \frac{3 \sqrt{5} }{3} [/tex]
[tex] = \sqrt{5} [/tex]
