Answer:
The new volume is 2415 mL
Explanation:
The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases.
Boyle's law says that the volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure and is expressed mathematically as:
P * V = k
Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:
[tex]\frac{V}{T} =k[/tex]
Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the gas pressure increases. And when the temperature is decreased, the gas pressure decreases. This can be expressed mathematically in the following way:
[tex]\frac{P}{T} =k[/tex]
Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:
[tex]\frac{P*V}{T} =k[/tex]
Having two different states, an initial state and an final state, it is true:
[tex]\frac{P1*V1}{T1} =\frac{P2*V2}{T2}[/tex]
In this case:
- P1= 0.9 atm
- V1=4,600 mL= 4.6 L (being 1 L=1,000 mL)
- T1= 195 °C= 468 °K (being 0°C=273°K)
The final state 2 is in STP conditions:
- P2= 1 atm
- V2= ?
- T2= 0°C= 273 °K
Replacing:
[tex]\frac{0.9 atm*4.6L}{468K} =\frac{1 atm*V2}{273K}[/tex]
Solving:
[tex]V2=\frac{0.9 atm*4.6L}{468K}*\frac{273K}{1 atm}[/tex]
V2= 2.415 L =2,415 mL
The new volume is 2415 mL
