Answer:
65.7g of chlorobenzene is expected to be produced.
Explanation:
The reaction equation is:
[tex]C_{6} H_{6} (l) + Cl_{2} (g)[/tex] → [tex]C_{6} H_{5}Cl (s) + HCl(g)[/tex]
Mole ratio of C6H6 to CH5Cl is 1 : 1: that is for every 1 mole of benzene used in the reaction, 1 molee of chlorobenzene is produced.
1 mole of C6H6 - 78.11 g
?? mole of C6H6 - 45.6 g ⇒ [tex]\frac{45.6}{78.11}[/tex] = 0.58 moles used in reaction
Consequently,
1 mole of chlorobenzene - 112.56 g
0.58 moles of chlorobenzene = 112.56 × 0.58
= 65.7g
The theoretical yield should be 65.7g.
The reaction equation is
C6H6(l) + Cl2(g) → C6H5Cl(s) = HCl (g)
Here
The mole ratio of C6H6 to CH5Cl is 1: 1 i.e. every 1 mole of benzene used in the reaction, 1 moles of chlorobenzene is produced.
Since 1 mole of C6H6 - 78.11 g
So, for 45.6g, it should be
= 45.6/78.11
= 0.58 moles
Now
1 mole of chlorobenzene - 112.56 g
So, for 0.58 moles it should be
= 112.56 × 0.58
= 65.7g
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