Answer:
The average acceleration of train is [tex]5.34\ m/s^2[/tex]
Step-by-step explanation:
We have,
A train that slows down from 15 m/s to 8.6 m/s in 1.2 s. It means that 15 m/s is its initial velocity and 8.6 m/s is its final velocity.
It is required to find the average acceleration of the train.
[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{(8.6-15)\ m/s}{1.2\ s}\\\\a=-5.34\ m/s^2[/tex]
The average acceleration of train is [tex]5.34\ m/s^2[/tex]. Negative signs shows that the train is decelerating.
