Angle D is a circumscribed angle of circle O.

Circle O is shown. Triangle A C B is inscribed within circle O. Side A B goes through point O. The length of A C is 15 and the length of C B is 8. Angle A C B is a right angle. Line segment O E is a radius. Tangents B D and E D intersect at point D outside of the circle to form kite O B D E. Angles O B D and D E O are right angles. The length of E D is 5.

What is the perimeter of kite OBDE?

17 units
23 units
27 units
60 units

Since angle D is a circumscribed angle of circle O, the perimeter of kite OBDE is equal to 27 units in accordance with Pythagorean's Theorem.

How to calculate the perimeter of kite OBDE.

In order to determine the perimeter of kite OBDE, we would apply Pythagorean's Theorem because angles OBD and DEO are right angles.

Mathematically, Pythagorean Theorem is given by this formula:

c² = a² + b²

Where:

h is the hypotenuse.

a is the adjacent side.

b is the opposite side.

Given the following data:

Length of AC = 15 units.

Length of CB = 8 units.

Length of ED = 5 units.

Substituting the given parameters into the formula, we have;

c² = 15² + 8²

c² = 225+64

c =√289

c = 17 units.

Since a kite is a quadrilateral with four (4) equal sides and two (2) congruent sides, we can deduce the following:

Side OB = OE = 1/2 × 17 = 8.5 units.

Side BD = ED = 5 units.

Therefore, the perimeter of kite OBDE is given by:

Perimeter = 17 + (5 + 5)

Perimeter = 17 + 10

Perimeter = 27 units.

Read more on Pythagorean Theorem here: https://brainly.com/question/16176867