What is the force exerted on a moving charge of –2.0 μC at a 20° angle through a magnetic field of 3.0 × 10–4 T with a velocity of 5.0 × 106 m/s?

Respuesta :

Answer:

The force exerted on a moving charge is [tex]1.02\times 10^{-3}\ N[/tex].                

Explanation:

We have,

Charge, [tex]q=-2\ \mu C[/tex]

Magnetic field, [tex]B=3\times 10^{-4}\ T[/tex]

Velocity of charged particle, [tex]v=5\times 10^6\ m/s[/tex]

Angle through the magnetic field, [tex]\theta=20^{\circ}[/tex]

It is required to find the force exerted on a moving charge. Due to the motion in charge, magnetic force acts on it. It can be given by :

[tex]F=qvB\sin\theta[/tex]

Plugging all values above

[tex]F=-2\times 10^{-6}\times 5\times 10^6\times 3\times 10^{-4}\times \sin (20)\\\\F=1.02\times 10^{-3}\ N[/tex]

So, force exerted on a moving charge is [tex]1.02\times 10^{-3}\ N[/tex].

Answer:

B. 1.0 x 10^-3

Explanation: