Maricopa's Success scholarship fund receives a gift of $ 115000. The money is invested in stocks, bonds, and CDs. CDs pay 5.75 % interest, bonds pay 5.8 % interest, and stocks pay 6.4 % interest. Maricopa Success invests $ 30000 more in bonds than in CDs. If the annual income from the investments is $ 6930 , how much was invested in each account?

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Answer:

Amount invested in CDs is $20000.

Amount invested in Bonds is $50000.

Amount invested in Stocks is $45000.

Step-by-step explanation:

Let amount invested in CDs be $x.

Interest received from CDs is [tex]5.75 \%[/tex]

[tex]\Rightarrow \text{Interest from CDs} = x \times \dfrac{5.75}{100} ...... (1)[/tex]

As per question, amount invested in bonds is $(x+30000).

Interest received from bonds is [tex]5.8 \%[/tex].

[tex]\Rightarrow \text{Interest from bonds} = (x+30000) \times \dfrac{5.8}{100} ...... (2)[/tex]

Total amount is $115000.

So, amount invested in stocks = Total amount - Amount invested in CDs and Bonds

[tex]\Rightarrow 115000 - x - (x+30000)\\ \Rightarrow (85000-2x)[/tex]

Interest received from stocks is [tex]6.4 \%[/tex] [tex]\Rightarrow \text{Interest from Stocks} = (85000-2x) \times \dfrac{6.4}{100} ...... (3)[/tex]

Total annual income from interest is $6930.

Adding equations (1), (2) and (3) and putting it equal to 6930.

[tex]\Rightarrow x \times \dfrac{5.75}{100} + (x+30000) \times \dfrac{5.8}{100} + (85000-2x) \times \dfrac{6.4}{100} = 6930\\\Rightarrow (12.8x - 11.55x) = 544000 + 174000 - 693000\\\Rightarrow 1.25x = 25000\\\Rightarrow x = 20000[/tex]

Amount invested in CDs is $20000.

Amount invested in Bonds is (x + 30000)= $20000+$30000 = $50000.

Amount invested in Stocks is [tex]\(85000 - 2 \times x\) = \(85000 - 2 \times 20000\)[/tex]= $45000.