Answer:
[tex]a_{50}=290[/tex]
Step-by-step explanation:
Notice that we are in the presence of an arithmetic sequence (there is a common difference of 6 between a term and the next). So thisis an arithmetic sequence with first term [tex]a_1=-4[/tex]. and common difference "d" = 6.
Recall now the formula for the nth term ([tex]a_n[/tex]) of an arithmetic sequence:
[tex]a_n=a_1+(n-1)\,d[/tex]
Then, using our values in the formula, we get:
[tex]a_n=a_1+(n-1)\,d\\a_{50}=-4+(50-1)\,6\\a_{50}=-4+(49)\,6\\a_{50}=290[/tex]
