Answer: A. 0.0375
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} O_2=\frac{3.00g}{32g/mol}=0.094moles[/tex]
[tex]2N_2+5O_2(g)\rightarrow 2N_2O_5[/tex]
According to stoichiometry :
As 5 moles of [tex]O_2[/tex] give = 2 moles of [tex]N_2O_5[/tex]
Thus 0.094 moles of [tex]O_2[/tex] give =[tex]\frac{2}{5}\times 0.094=0.0375moles[/tex] of [tex]N_2O_5[/tex]
Thus 0.0375 moles of [tex]N_2O_5[/tex] will be produced when 3.00g of O₂ react completely
