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2. LiBr (aq) + Cl2(g) → LiCl (aq) + Br2 (l)

How many moles of chlorine will be needed to produce 3.50 moles of lithium chloride? ________


Can someone please show the work and the answer much appreciated

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jufsanabriasa

Answer:

1.75moles of Cl₂ are needed

Explanation:

Based on the reaction:

2 LiBr (aq) + Cl₂(g) → 2 LiCl(aq) + Br₂(l)

2 moles of LiBr and 1 mole of chlorine produce 2 moles of lithium chloride and 1 mole of bromine.

Thus, when 3.50 moles of LiCl are produced, moles of chlorine needed are:

3.50 moles of LiCl × (1mol Cl₂ / 2mol LiCl) = 1.75moles of Cl₂ are needed

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