Answer:
1 mole of Sn is required to react with 40 gram of HF
Explanation:
It is given that molar mass of HF is 20.01 g/mol
Mass of HF is 40 gram
So number of of HF is
Number of moles [tex]=\frac{mass\ in\ gram}{molar\ mass}[/tex]
[tex]=\frac{40}{20.01}=1.9999=2moles[/tex]
When reaction between HF and Sn takes place
[tex]Sn+2HF\rightarrow SnF_2+H_2[/tex]
From the reaction it is clear that 1 mole Sn require 2 moles HF
Therefore 2 moles of HF require 1 mole Sn
