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A 10 kg block is attached to a light cord that is wrapped around the pulley of an electric motor, as shown above. At what rate is the motor doing work when it is pulling the block upward with an instantaneous speed of 3 m/s and an upward acceleration of 2 m/s2 ?

Respuesta :

Limosa

Answer:

360 W.

Explanation:

[tex]The\;formula\;to\;find\;the\;Power\;is: P=Fv[/tex]

In which,

P = Power.

F = Force.

v = velocity.

So, we have to apply values in the formula.

         [tex]P=Fv[/tex]

         [tex]F=10\times(10+2)N[/tex]

         [tex]F=120N[/tex]

         [tex]v=3\;m/s\;that\;is\;already\;given[/tex]

[tex]Then,\;\;\;\;\;\;\;\;\;P=120\times3=360W[/tex]

So, the following answer is correct according to the explanation.

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