Respuesta :
Answer:
.0676
Step-by-step explanation:
Both events are independent b/c of the ball replacement; therefore, you simply take the probability of choosing 1 red ball & square (x^2) it (or multiply it by itself.) (13/50)^2=169/2500=.0676
The probability of selecting 2 red balls when the ball is replaced each time [tex]0.0676[/tex].
Number of white balls [tex]= 10[/tex].
Number of blue balls [tex]= 12[/tex].
Number of red balls [tex]= 13[/tex].
Number of yellow balls [tex]= 7[/tex].
Number of green balls [tex]= 8[/tex].
So, total balls [tex]= 10+12+13+7+8=50[/tex].
Since, the ball is replaced each time. So, the probability is [tex]\frac{13}{50}[/tex] every time.
For 2 red balls, probability [tex]= \frac{13}{50} \times \frac{13}{50}[/tex]
[tex]= \frac{169}{2500}[/tex]
[tex]=0.0676[/tex]
So, the probability of selecting 2 red balls is [tex]\frac{169}{2500}=0.0676[/tex].
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